Unit 22: Hydroxy Compounds — Short Questions
12th Class Chemistry · Unit 22: Hydroxy Compounds
iv. 2-methylpropan-2-ol, (CH₃)₃COH. Its –OH is attached to a carbon that is bonded to three other carbons (three methyl groups), the general formula R₃COH, which defines a tertiary alcohol.
ii. ethane-1,2-diol and v. propan-1-ol are both primary alcohols (R-CH₂OH); primary alcohols are oxidised first to an aldehyde and, on further (excess) oxidation with acidified K₂Cr₂O₇ or KMnO₄, to the corresponding carboxylic acid.
i. butan-2-ol, iii. 2-methylpentan-3-ol and vi. propan-2-ol are all secondary alcohols (R₂CHOH); secondary alcohols are oxidised by acidified K₂Cr₂O₇/KMnO₄ to ketones.
The azo group is the –N=N– linkage joining the two aromatic rings in Q, i.e. the nitrogen–nitrogen double bond between the phenyl ring (from P) and the hydroxyphenyl ring (from phenol): C₆H₅–[N=N]–C₆H₄–OH.
Azo compounds such as Q are used as synthetic dyes/colourants, for example to dye textiles and to colour foods.
Compound A is chlorocyclohexane, C₆H₁₁Cl — a cyclohexane ring with one hydrogen replaced by a chlorine atom, formed by free-radical substitution of cyclohexane with Cl₂ (UV light).
Heating cyclohexanol with concentrated sulfuric acid (H₂SO₄) or concentrated phosphoric acid (H₃PO₄); alternatively, passing the alcohol vapour over a heated aluminium oxide (Al₂O₃) catalyst.
C₆H₁₁OH → C₆H₁₀ + H₂O (heated with conc. H₂SO₄ or Al₂O₃ catalyst)
A, (CH₃)₃C–OH, is a tertiary alcohol (the –OH carbon is bonded to three other carbons). B, CH₃CH₂CH(OH)CH₃, is a secondary alcohol (the –OH carbon is bonded to two other carbons).
2-methylpropan-2-ol (tert-butyl alcohol).
C, butan-1-ol, CH₃CH₂CH₂CH₂OH, is a primary alcohol, so oxidation (e.g. by distillation with acidified K₂Cr₂O₇) gives the aldehyde butanal: CH₃CH₂CH₂CHO. (D, 2-methylpropan-1-ol, is also primary and would equally oxidise to an aldehyde, 2-methylpropanal.)
Dehydration is the removal of a water molecule from an alcohol; it is an elimination reaction. Dehydrating an alcohol produces an alkene.
Heat the alcohol with concentrated sulfuric acid (H₂SO₄) or concentrated phosphoric acid (H₃PO₄); alternatively, pass the alcohol vapour over a heated aluminium oxide (Al₂O₃) catalyst.
The –OH group of phenol donates one of oxygen's lone pairs into the aromatic ring (delocalisation into the π system), increasing the electron density of the ring. This activates the ring towards electrophilic attack, so phenol undergoes nitration far more readily (under milder conditions) than benzene. When phenol is nitrated with concentrated HNO₃ at room temperature, the product is 2,4,6-trinitrophenol.
Phenol is markedly more acidic than ethanol because its conjugate base, the phenoxide ion, is stabilised by delocalisation of the negative charge on oxygen into the aromatic ring, whereas ethanol's conjugate base, the ethoxide ion, is destabilised by the electron-donating (+I) ethyl group. Phenol is therefore acidic enough to be deprotonated by the weak base NaOH, forming soluble sodium phenoxide and water, while ethanol (less acidic than even water) cannot be deprotonated by NaOH.
CH₃OH + SOCl₂ → CH₃Cl + SO₂ + HCl
CH₃OH + PCl₅ → CH₃Cl + POCl₃ + HCl
Propan-1-ol (a primary alcohol) is oxidised to propanal by heating with acidified K₂Cr₂O₇ (or KMnO₄) and distilling off the aldehyde as it forms (before it is further oxidised to propanoic acid): CH₃CH₂CH₂OH + [O] → CH₃CH₂CHO + H₂O.