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Unit 19: Basics of Organic Chemistry — Long Questions

12th Class Chemistry · Unit 19: Basics of Organic Chemistry

Q3.a.A compound C₆H₅CH₃ (toluene) reacts with Cl₂ in the presence of sunlight to form the product C₆H₅CCl₃. Name the mechanism of the reaction. Give its different steps.
Q4.Explain the difference between homolytic and heterolytic fissions of a covalent bond.

Homolytic fission (homolysis) occurs when a nonpolar covalent bond breaks such that the two shared (bonding) electrons are distributed equally, one to each atom; each resulting atom or group carries an unpaired electron and is called a free radical, e.g. Cl-Cl → Cl• + Cl•, or CH₃-H → CH₃• + H•. Free radicals are highly reactive reaction intermediates because their unpaired electron tends to pair up. Heterolytic fission (heterolysis) occurs when a polar covalent bond breaks such that the two shared electrons are distributed unequally — one atom keeps both electrons and becomes negatively charged, while the other atom becomes deficient in one electron and acquires a positive charge. If the positively charged species is a carbon atom, it is called a carbocation, formed when carbon is bonded to a more electronegative heteroatom (e.g. CH₃-Cl → CH₃⁺ + Cl⁻); if carbon instead ends up negatively charged, it is called a carbanion, formed when carbon is bonded to a less electronegative atom such as a metal (e.g. Li, Mg). In short, homolysis needs a nonpolar bond and gives neutral free radicals, while heterolysis needs a polar bond and gives a cation–anion pair.

Q5.Discuss cis-trans isomerism. Explain with two examples.

Cis-trans (geometrical) isomerism is a type of stereoisomerism found in open-chain compounds that arises from restricted rotation about a C=C double bond. A double bond consists of a σ bond and a π bond; the π bond (formed by sideways overlap of p orbitals) locks the two double-bonded carbons and the groups attached to them in one fixed plane. Free rotation about the double bond would require breaking the π bond, which needs a large amount of energy (about 263 kJ/mol for but-2-ene), not available at room temperature, so rotation is restricted. Cis-trans isomerism is possible only if each of the two doubly bonded carbon atoms carries two different groups. The cis isomer has the two similar/reference groups on the same side of the double bond, while the trans isomer has them on opposite sides; the two isomers cannot interconvert without breaking the π bond, and they differ in physical properties (m.p., b.p., density, dipole moment) and chemical reactivity (trans isomers are generally more stable than cis). Example 1: But-2-ene, CH₃-CH=CH-CH₃. In cis-but-2-ene the two CH₃ groups are on the same side of the double bond; in trans-but-2-ene they are on opposite sides. Example 2: 1,2-dibromoethene, CHBr=CHBr (one of the two possible structures of C₂H₂Br₂). In cis-1,2-dibromoethene both Br atoms are on the same side; in trans-1,2-dibromoethene the Br atoms are on opposite sides.

Q6.Describe the phenomenon of optical activity. Explain with an example.

Optical isomers are stereoisomers that have identical physical and chemical properties except for their ability to rotate the plane of plane-polarised light (PPL); this property is called optical activity, and compounds showing it are optically active. PPL is monochromatic light vibrating in a single plane; when passed through a solution of an optically active compound in a polarimeter, the plane of polarisation is rotated either clockwise (dextrorotatory, symbol (+)) or anticlockwise (levorotatory, symbol (-)). The basic structural requirement for optical activity is that the molecule must be non-superimposable on its mirror image, i.e. it must be chiral (asymmetric) — commonly because it contains a chiral carbon, a carbon bonded to four different atoms or groups (if a molecule has only one chiral carbon it is always chiral and hence optically active). Example: lactic acid, CH₃-CH(OH)-COOH, has one chiral carbon bonded to four different groups — CH₃, H, OH and COOH. It therefore exists as two optically active stereoisomers, (+)-lactic acid (dextrorotatory) and (-)-lactic acid (levorotatory), which are non-superimposable mirror images (enantiomers) of each other, identical in physical and chemical properties but rotating plane-polarised light equally in opposite directions.

Q7.What is the difference between racemic mixture and meso compound? Draw the structures of enantiomers and meso form of [as printed] lactic acid.