Unit 1: Real Numbers — Exercise 1 3
9th Class Mathematics · Unit 1: Real Numbers
1.3.1.The sum of three consecutive integers is forty-two, find the three integers.
Given
Consecutive integers
x, (x+1), (x+2)
Working
x+(x+1)+(x+2)=42
3x+3=42 ⇒ 3x=39 ⇒ x=13
Result
Integers
13, 14, 15
1.3.2.The diagram shows right angled \triangle ABC in which the length of \overline{AC} is (\sqrt3+\sqrt5)\ cm. The area of \triangle ABC is (1+\sqrt{15})\ cm^2. Find the length \overline{AB} in the form (a\sqrt3+b\sqrt5)\ cm, where a and b are integers.
Given
overline{AC}=(sqrt3+sqrt5) cm,quad Area=(1+sqrt{15}) cm2
Formula
Area of right triangle
Area=frac12 × overline{AC} × overline{AB}
Working
(1+sqrt{15})=frac12(sqrt3+sqrt5)overline{AB} ⇒ (2+2sqrt{15})=(sqrt3+sqrt5)overline{AB}
overline{AB}=frac{2+2sqrt{15}{sqrt3+sqrt5} × sqrt3-sqrt5sqrt3-sqrt5=2sqrt3-2sqrt5+6sqrt5-10sqrt3-2
Result
AB
overline{AB}=(4sqrt3-2sqrt5) cm
1.3.3.A rectangle has sides of length 2+\sqrt{18}\ m and \left(5-\frac{4}{\sqrt2}\right)\ m. Express the area of the rectangle in the form a+b\sqrt2, where a and b are integers.
Formula
Area
Area=L × W=(2+sqrt{18}) × left(5-4sqrt2right)
=10-8sqrt2+5sqrt{18}-sqrt{18}left(4sqrt2right)=10-4sqrt2+15sqrt2-12
Result
Area
(11sqrt2-2) m2
1.3.4.Find two numbers whose sum is 68 and difference is 22.
Given
x+y=68,quad x-y=22
Adding both
2x=90 ⇒ x=45
Subtracting both
2y=46 ⇒ y=23
Result
x=45, y=23
1.3.5.The weather in Lahore was unusually warm during the summer of 2024. The TV news reported temperature as high as 48°C. By using the formula, (°F=\frac{9}{5}°C+32) find the temperature as Fahrenheit scale.
Formula
{}circF=frac95{}circC+32
Working
{}circF=frac95 × 48+32
Result
{}circF=118.4
1.3.6.The sum of the ages of the father and son is 72 years. Six years ago, the father's age was 2 times the age of the son. What was son's age six years ago?
Given
Son's current age=x,quad Father's current age=72-x
Working
Six years ago
66-x=2(x-6)
66-x=2x-12 ⇒ 78=3x ⇒ x=26
Result
Son's age six years ago
26-6=20 years
1.3.7.Mirha bought a toy for Rs. 1500 and sold for Rs. 1520. What was her profit percentage?
Given
CP=1500,quad SP=1520
Formula
Profit
Profit=SP-CP=1520-1500=20
Working
Profit \%
201500 × 100%
Result
1.33%
1.3.8.The annual income of Tayyab is Rs. 9,60,000, while the exempted amount is Rs. 1,30,000. How much tax would he have to pay at the rate of 0.75%?
Formula
Taxable income
Total Income-Exempted Amount
Working
960000-130000=830000
Formula
Tax amount
Taxable Income × Tax Rate
Working
830000 × 0.0075
Result
Tax
Rs. 6225
1.3.9.Find the compound markup on Rs. 3,75,000 for one year at the rate of 14% compounded annually.
Given
P=375000,quad R=0.14,quad T=1
Formula
Compound interest
CI=P(1+R)T-P
Working
CI=375000(1.14)1-375000
Result
CI=Rs. 52500