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Unit 12: Nuclear and Particle Physics — Short Questions

11th Class Physics · Unit 12: Nuclear and Particle Physics

Exercise Short Questions

12.1.What do different isotopes of a given element have in common? How are they different?

Common Different isotopes of a given element have the same number of protons (atomic number) in their atomic nuclei, which means they have the same chemical properties.
Different: They differ in the number of neutrons in their nuclei, resulting in different atomic masses (or mass numbers). This difference in neutron number affects their physical properties, such as mass, density, and stability.

12.2.Identify the element that has 87 nucleons and 50 neutrons.

To identify the element Nucleons = protons + neutrons = 87 = atomic mass
So, Protons = A - N = 87 - 50 = 37
The element with atomic number 37 is Rubidium (37 Rb)

12.3.What are the similarities and differences between the strong nuclear force and the electric force?

Similarities (i) Both are fundamental forces in nature.
(ii) Both forces act between particles.
(iii) Both obey conservation of energy and momentum.
(iv) Both follow inverse square law.
Differences:
(i) Range: Strong nuclear force has a short range (acts over nuclear distances, ≈ 10-15 m), while electric force has a long range (acts over much larger distances).
(ii) Strength: Strong nuclear force is much stronger than electric force at short ranges, but electric force dominates at larger distances.
(iii) Charge dependence: Strong nuclear force acts between quarks and nucleons (no charge dependence), while electric force acts between charged particles dependent on charge.
(iv) Effect on Protons/Neutrons: The strong nuclear force holds quarks together inside protons/neutrons and binds nucleons in the nucleus, overcoming electric repulsion between positively charged protons.

12.4.Fill in the missing particle or nucleus: (a) 45₂₀Ca → ?+e +v̄ (b) 58₂₉Cu → ?+γ

(a) This represents beta minus decay, where a neutron decays into a proton, emitting an electron and antineutrino. The atomic number increases by one and mass number remains same. The resulting nucleus is scandium (⁴⁵Sc).
(b) In 58₂₉Cu → 58₂₉Cu+γ. Since emission of γ ray photon neither change its charge number nor mass number so, only the energy state will change (i.e. cu )

12.5.Why neutrino must be released in the positron emission?

In beta plus (β⁺) decay (positron emission), a proton in the nucleus is converted into a neutron, a positron (e⁺), and a neutrino (ν):
P → n + e⁺ + ν
A neutrino is released in positron emission to conserve energy and momentum.

12.6.Distinguish between fermions and bosons.

Fermions (i) Particles with half-integer spin (1/2, 3/2, etc.).
(ii) Follow fermi-Dirac statistics.
(iii) Include particles like electrons, protons, neutrons, and quarks.
(iv) Obey the Pauli exclusion principle (no two fermions can occupy the same quantum state).
Bosons:
(i) Particles with integer spin (0, 1, etc.).
(ii) Follow Bose-Einstein statistics.
(iii) Include particles like photons, gluons, and mesons.
(iv) Do not obey the Pauli exclusion principle (multiple bosons can occupy the same quantum state).

12.7.How does strong force hold the nucleus?

The strong nuclear force holds the nucleus together by binding protons and neutrons, overcoming the repulsion between positively charged protons.
The strong force is due to particles called gluons, which are exchanged between quarks. Quarks are building blocks of protons and neutrons.

12.8.Can there be pair production for photons having energy 20keV? Explain briefly.

No, pair production requires a photon energy of at least 1.022 MeV (2 × 0.511 MeV, the rest mass energy of an electron positron pair).
Since 20 keV is much less than 1.022 MeV, pair production is not possible with a photon of this energy.

12.9.What is the difference between beta particle and electron?

Beta particle and electron are essentially the same particle. The difference lies in their origin:
(i) Electron: Typically refers to constituent of atom, orbiting the nucleus.
(ii) Beta particle: Specifically refers to electrons (β⁻) or positrons (β⁺) emitted from the nucleus during radioactive decay.
So, all beta particles are electrons or positron, but not all electrons are beta particles.

12.10.How do a proton and a neutron convert to each other?

A proton and a neutron can convert to each other through weak nuclear force.
(i) Proton to neutron:
Through beta plus (β⁺) decay a proton can convert into a neutron.
p → n + e⁺ + ν
(ii) Neutron to Proton:
Through beta minus (β⁻) decay, a neutron can convert into a proton.
n → p + e⁻ + v̄

12.11.Why does beta-decay have a continuous energy spectrum and alpha-decay have a discrete energy spectrum?

Beta decay has a continuous energy spectrum because the energy is shared between the beta particle and the neutrino (or antineutrino) in varying proportions. Each decay event distributes the energy differently, resulting in a range of energies for the beta particles.
Alpha decay has a discrete energy spectrum because the alpha particle is emitted with a specific energy, determined by the difference in nuclear binding energies between the parent and daughter nuclei. Since alpha decay typically involves a two-body decay (parent nucleus → alpha particle + daughter nucleus), the alpha particle carries all the energy.

12.12.Differentiate between hadron and leptons with examples.

Hadrons (i) Particles that interact via the strong nuclear force.
(ii) Composed of quarks.
(iii) Examples:
Protons (p), neutrons.
Pions (π mesons)
Leptons:
(i) Particles that do not interact via the strong nuclear force.
(ii) Fundamental particles, not composed of quarks.
(iii) Examples:
Electrons (e⁻)
Muons (μ)
Neutrinos (ν)

12.13.Why electron-positron pair cannot decay into a single photon.

An electron-positron pair cannot decay into a single photon because it would violate the law of conservation of momentum.
As the total linear momentum is zero before conversion. So, two photons should be emitted to move in opposite direction with equal magnitude of momentum to conserve momentum.
The most common process is:
e⁻ + e⁺ → γ + γ

12.14.State the role of Higgs Boson in the generation of mass in modern physics theories.

The Higgs boson is linked to the Higgs field, a field that permeates space. Particles gain mass by interacting with this field. The more a particle interacts with the Higgs field, the more mass it acquires. The discovery of the Higgs boson confirmed this mechanism, explaining why some particles like w, w' and z bosons have mass while others (like photons) do not.

12.15.What are mesons? Give examples.

Mesons are a type of hadron, which are particles made up of one quark and one antiquark. They are bosons (integer spin particles) and interact via the strong nuclear force.
Examples:
(i) Pions (π⁺, π⁻, π⁰)
(ii) Kaons (K⁺, K⁻, K⁰)
Mesons are unstable and decay quickly into other particles.

SLO Based Additional Short Questions + Past papers Short Questions of Punjab Boards

Structure of nucleus

Q1.Differentiate between atomic number and mass number.

Atomic Number The number of protons or electrons present in any atom is called its atomic number. Atomic number is also called charge number. It is usually denoted by a letter Z.
Mass Number:
The sum of protons and neutrons present in the nucleus of an atom is called its mass number. It is also called as nucleon number and is denoted by a letter A.

Q2.In ²³⁵₉₂U, find: (i) Atomic number (ii) Charge number (iii) Number of neutrons (iv) Number of electrons

Atomic number 92
Number of neutrons 143
Number of electrons 92
Charge Number 92

Q3.How the nucleus of ²³⁵₉₂U differs from a nucleus of ²³⁸₉₂U?

²³⁵₉₂U and ²³⁸₉₂U have some charge number i.e. Z = 92. However, the number of neutrons in ²³⁵₉₂U are N = A – Z = 235 – 92 = 143
The numbers of neutrons in ²³⁸U are N = A – Z = 238 – 92 = 146
Hence, the ²³⁵U and ²³⁸U differs by three (3) neutrons. It shows that they are isotopes containing same number of electrons or protons i.e. charge number Z but mass number A is different.

Radio activity

Q4.Who discovered natural radioactivity?

Henri Becquerel discovered the phenomena of radioactivity in 1896 in Uranium. It was found that it emits three type of radiations known as α, β and γ rays.

Q5.What happens to the nucleus, which emits an α-particle?

When a nucleus emits an α – particle (also called α – decay)' its mass number decreases by 4 while charge number by 2. An α – decay of radium ₈₈Ra is converted into
Radon ²²⁶₈₈Ra → ²²²₈₆Rn is given as follow:
²²⁶Ra → ²²²Ra + ⁴He

Q6.What is γ-ray?

It is a high frequency electromagnetic radiation. Its origin is the nucleus. When an excited nucleus returns back to its ground state, it give rise to emission of γ-radiations. The mass number and charge number remain same during γ-ray emission.

Q7.Write any two properties of α – particles.

(i) They are massive and have intense ionizing power during interaction with the matter.
(ii) Due to their large mass, their penetration is very small.

Q8.Write any two properties of β-particles.

(i) Beta particles are regarded as electrons. Due to smaller charge as compared to α - particles, the ionizing property of β - particles is about 100 times less than that of α - particle
(ii) β - particle can radiate energy when are slowed down by electric field of the charged particles.

Q9.In what ways γ-rays may interact with the matter?

(i) Gamma rays at very high energy (≥ 1.02 MeV) can cause phenomena of pair – production.
(ii) At intermediate energies they can show Compton scattering effect
(iii) At low energies (e.g. < 0.5 MeV) they can remove electrons from only metallic surface through photoelectric effect.

Decay constant

Q10.What is decay constant? Write its units.

The fraction of the total is number of atoms decayed per unit time is called decay constant. It is denoted by λ and it measured in sec⁻¹

Hadrons and Leptons

Q11.Differentiate between Hadrons & Leptons.

Hadrons are not elementary particles. They are composed of other elementary particles called quarks. The examples of hadrons are protons, neutrons, mesons etc. they experience strong nuclear force.
Leptons are the elementary particles. They do not experience strong nuclear force. Family of leptons include electrons, Muons and neutrinos.

Constructed Response Questions

12.1.Is meson or boson fermion? Give reason.

Mesons are bosons, not fermions.
Reason: Mesons are composed of one quark and one antiquark, resulting in an integer spin (0,1,2….), which classifies them as bosons.

12.2.Why does an alpha emitter emit alpha particles instead of four separate nucleons?

Alpha particles (2 protons + 2 neutrons) are emitted instead of four separate nucleons because:
(i) Binding energy: The alpha particle has a high binding energy per nucleon, making it a stable and energetically favorable configuration.
(ii) Strong nuclear force: The strong nuclear force holds the two protons and two neutrons together in the alpha particle, making it more likely to be emitted as a single unit.
Emitting an alpha particle is more energetically favorable than emitting four separate nucleons, which would require more energy to overcome the strong nuclear force.

12.3.Which is more energetic alpha decay or beta decay? Justify your answer.

Alpha decay is generally more energetic than beta decay due to the larger mass and charge of alpha particles, resulting in higher kinetic energy release.

12.4.A nucleus undergoes gamma decay, emitting gamma? Ray photon with energy 1.5MeV. Calculate. (i) Frequency of Gamma ray (ii) Wavelength of Gamma ray (iii) Momentum of Gamma ray

Given energy of gamma ray photon:
1.5 MeV = 1.5 × 10⁶ × 1.6 × 10⁻¹⁹ J
= 2.4 × 10⁻¹³ J
As (1₈ᵥ = 1.6 × 10⁻¹⁹ J)
Frequency (f): ?
E = hf
f = E / h
= (2.4 × 10⁻¹³ J) / (6.626 × 10⁻³⁴ Js)
= 3.62 × 10²⁰ Hz
Wavelength (λ):
λ = c / f
= (3 × 10⁸ m/s) / (3.62 × 10²⁰ Hz)
= 8.28 × 10⁻¹³ m
Momentum (p):
p = E /c
= (2.4 × 10⁻¹³ J) / (3 × 10⁸ m/s)
= 8 × 10⁻²² kg m/s

12.5.Why does the α-particles not make physical contact with the nucleus when headed directly towards it?

Alpha particles don't make physical contact with the nucleus when headed directly towards it due to the electrostatic repulsion between the positively charged alpha particle and the positively charged nucleus.
As the alpha particle approaches the nucleus, the electrostatic repulsive force increases, causing the alpha particle to be repelled or deflected before it can physically touch the nucleus.

Comprehensive Questions

12.1.What is meant by radioactivity? Compare the properties and behaviour of three types of radiations.

See Q.4 of theory

12.2.Elaborate the phenomenon of beta-positive decay and beta-negative decay with examples.

See Q.5 of theory.

12.3.What is the difference between matter and anti-matter? Discuss reasons why our universe is almost entirely composed of matter.

See Q.3 of theory.

12.4.Explain the phenomenon of pair annihilation with an example. Explain the utility of its principle in the medical field.

See Q.4 of theory.

12.5.Explain the law of conservation of energy and momentum in electron-positron pair annihilation.

See Q.4 of theory.

12.6.Describe protons and neutrons in terms of their quark composition.

See Q.8 of theory.

12.7.Describe four fundamental forces in nature.

See Q.2 of theory.

12.8.Describe the classification of elementary particles.

See Q.7 of theory.