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Learn/ O Level Mathematics/ Past Papers/ 2023/ Oct/Nov 2023 /Paper 1 (Variant 2)

Paper 1 — Variant 2

O Level Mathematics · 4024/12 · Oct/Nov 2023

Question Paper

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Mark Scheme

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Questions

12 of 24 questions shown here, checked against the paper. The others are in the PDF above — they contain diagrams or maths we could not yet verify, and we would rather show you the original than a transcription we are not sure of.

4
Sonu records the temperature, in °C, at midnight every day for 12 days. Here are the results in order, starting with the coldest. −6-6 −5-5 −3-3 −2-2 −1-1 −1-1 TT 55 55 66 66 77
4(a) [1]
Find the range of the temperatures.
4(b) [1]
The median temperature is 11 °C. Find the value of TT.
5 [2]
Anna and Ria share some money in the ratio 5:95 : 9. Ria receives $8\$8 more than Anna. Work out the total amount of money that is shared.
8
8(a) [1]
Write the number 0.004930.00493 in standard form.
8(b) [1]
Evaluate (4×109)×(2×10−2)(4 \times 10^{9}) \times (2 \times 10^{-2}). Give your answer in standard form.
9
9(a) [2]
Write 180180 as the product of its prime factors.
9(b) [1]
Expressed as the product of their prime factors, 36=22×3236 = 2^{2} \times 3^{2} and N=22×3×kN = 2^{2} \times 3 \times k, where k>3k > 3. 180180 is the lowest common multiple (LCM) of 3636 and NN. Find the value of kk.
10 [2]
By writing each number correct to 1 significant figure, estimate the value of 1240×3.811.2\sqrt{\frac{1240 \times 3.8}{11.2}}.
11 [2]
Solve 7m−13⩽87m - 13 \leqslant 8.
12 [3]
Solve the simultaneous equations. Show all your working. 5x+4y=145x + 4y = 14 3x−2y=153x - 2y = 15
13 [2]
A list of eight numbers has a mean of 1212. The first five numbers have a mean of 99. Find the sum of the three remaining numbers.
15
15(a) [2]
The second term of a linear sequence is 2828. The fifth term of the sequence is 1616. Find the first term, the third term and the fourth term of this sequence.
15(b) [2]
These are the first five terms of a different sequence. 33 99 1919 3333 5151 Find an expression for the nnth term of this sequence.
16
T=P−4T = \sqrt{P - 4}
16(a) [1]
Work out the value of TT when P=40P = 40.
16(b) [2]
Rearrange the formula to make PP the subject.
19 [2]
Express as a single fraction in its simplest form. x+18+3x4−5x16\frac{x+1}{8} + \frac{3x}{4} - \frac{5x}{16}
20
Factorise.
20(a) [2]
2cd+ce−6d−3e2cd + ce - 6d - 3e
20(b) [2]
3v2−27t23v^{2} - 27t^{2}

Published by Cambridge Assessment International Education. Reproduced for study use.