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Learn/ O Level Mathematics/ Past Papers/ 2020/ May/June 2020 /Paper 1 (Variant 1)

Paper 1 — Variant 1

O Level Mathematics · 4024/11 · May/June 2020

Question Paper

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Mark Scheme

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Questions

12 of 26 questions shown here, checked against the paper. The others are in the PDF above — they contain diagrams or maths we could not yet verify, and we would rather show you the original than a transcription we are not sure of.

3 [2]
The numbers in this sequence increase by the same amount each time. 1.41.4 2.32.3 3.23.2 Fill in the missing numbers.
4
4(a) [1]
Write 1125\frac{11}{25} as a percentage.
4(b) [2]
Find 12%12\% of 4040.
6 [2]
Safoora is buying some apples, bananas and peaches. She can buy packs of 6 apples, packs of 5 bananas, packs of 12 peaches. She needs to buy the same number of each fruit. Calculate the smallest number of packs of apples, bananas and peaches that she needs to buy.
7
Factorise.
7(a) [1]
6c3+9c6c^{3} + 9c
7(b) [2]
5ay−2bx−2by+5ax5ay - 2bx - 2by + 5ax
9
9(a) [2]
Write the ratio 7575 g : 33 kg in its simplest form.
9(b) [2]
In a tennis club the ratio number of junior members : number of senior members =7:10= 7 : 10. There are 18 more senior members than junior members. Calculate the total number of club members.
11 [2]
By writing each number correct to one significant figure, estimate the value of 21.86−9.64÷2.4721.86 - 9.64 \div 2.47.
13
13(a) [1]
During 2018, the population of a village increased from 200 to 250. Calculate the percentage increase in population.
13(b) [2]
The length of a rectangle is increased by 10%10\%. The width of the same rectangle is decreased by 10%10\%. Find the area of the new rectangle as a percentage of the area of the original rectangle.
16
16(a) [2]
Solve the equation 5−2x=125 - 2x = 12.
16(b) [2]
Find the integers that satisfy −5⩽3x⩽6-5 \leqslant 3x \leqslant 6.
17
f(x)=5−4xf(x) = 5 - 4x
17(a) [1]
Find f(−3)f(-3).
17(b) [2]
Find f−1(x)f^{-1}(x).
22 [1]
One solution of the equation sin⁡m∘=0.63\sin m^\circ = 0.63 is m=141m = 141, correct to the nearest whole number. Find the solution when 0<m<900 < m < 90. Give your answer correct to the nearest whole number.
23
23(a) [1]
The formula for the nnth term of a sequence is 2n32n^{3}. Find the 3rd term of this sequence.
23(b)
Here are the first four terms of another sequence. 43\frac{4}{3} 95\frac{9}{5} 167\frac{16}{7} 259\frac{25}{9}
23(b)(i) [1]
Write down the next term of this sequence.
23(b)(ii) [3]
Find a formula for the nnth term of this sequence.
26 [4]
Write as a single fraction in its simplest form. 2x+3x+4−53x−2\frac{2x+3}{x+4} - \frac{5}{3x-2}

Published by Cambridge Assessment International Education. Reproduced for study use.