Pure Mathematics 3 — Variant 1
A Level Mathematics · 9709/31 · May/June 2024
Questions
9 of 11 questions shown here, checked against the paper. The others are in the PDF above — they contain diagrams or maths we could not yet verify, and we would rather show you the original than a transcription we are not sure of.
1
[4]
Expand in ascending powers of , up to and including the term in , simplifying the coefficients.
2
[4]
Solve the equation . Give your answer correct to 2 decimal places.
5
[7]
The equation of a curve is for . Find and hence find the -coordinates of the stationary points of the curve.
6
6(a)
[2]
By sketching a suitable pair of graphs, show that the equation has exactly one root, denoted by , in the interval .
6(b)
[2]
Verify by calculation that lies between and .
6(c)
[1]
Show that if a sequence of values in the interval given by the iterative formula converges, then it converges to .
6(d)
[3]
Use this iterative formula with an initial value of to determine correct to 2 decimal places. Give the result of each iteration to 4 decimal places.
6(e)
[1]
State the minimum number of calculated iterations needed with this initial value to determine correct to 2 decimal places.
7
7(a)
[4]
On a single Argand diagram sketch the loci given by the equations and where and are complex numbers.
7(b)
[2]
Hence find the least value of for points on these loci. Give your answer in an exact form.
8
[7]
Use the substitution to find the exact value of . Give your answer in the form where and are rational numbers to be determined.
9
The equations of two straight lines and are and , where is a constant. The lines and are perpendicular.
9(a)
[1]
Show that . The lines and also intersect.
9(b)
[4]
Find the position vector of the point of intersection. The point has position vector .
9(c)
[2]
Show that lies on . The point is the image of after a reflection in the line .
9(d)
[2]
Find the position vector of .
10
10(a)
[3]
Given that , show that .
10(b)
[7]
Hence find the exact value of .
11
In a field there are 300 plants of a certain species, all of which can be infected by a particular disease. At time after the first plant is infected there are infected plants. The rate of change of is proportional to the product of the number of plants infected and the number of plants that are not yet infected. The variables and are treated as continuous, and it is given that and when .
11(a)
[2]
Show that and satisfy the differential equation .
11(b)
[9]
Using partial fractions, solve the differential equation and obtain an expression for in terms of a single logarithm involving .
Published by Cambridge Assessment International Education. Reproduced for study use.