Mechanics — Variant 2

A Level Mathematics · 9709/42 · Feb/March 2024

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Questions

4 of 7 questions shown here, checked against the paper. The others are in the PDF above — they contain diagrams or maths we could not yet verify, and we would rather show you the original than a transcription we are not sure of.

2
A particle is projected vertically upwards from horizontal ground. The speed of the particle 22 seconds after it is projected is 5m s−15 \text{m s}^{-1} and it is travelling downwards.
2(a) [2]
Find the speed of projection of the particle.
2(b) [2]
Find the distance travelled by the particle between the two times at which its speed is 10m s−110 \text{m s}^{-1}.
3 [5]
A crate of mass 600600 kg is being pulled up a line of greatest slope of a rough plane at a constant speed of 2m s−12 \text{m s}^{-1} by a rope attached to a winch. The plane is inclined at an angle of 30∘30^\circ to the horizontal and the rope is parallel to the plane. The winch is working at a constant rate of 88 kW. Find the coefficient of friction between the crate and the plane.
5
A particle moves in a straight line starting from a point OO. The velocity vm s−1v \text{m s}^{-1} of the particle tt s after leaving OO is given by v=t3−92t2+1v = t^{3} - \frac{9}{2}t^{2} + 1 for 0⩽t⩽40 \leqslant t \leqslant 4. You may assume that the velocity of the particle is positive for t<12t < \frac{1}{2}, is zero at t=12t = \frac{1}{2} and is negative for t>12t > \frac{1}{2}.
5(a) [4]
Find the distance travelled between t=0t = 0 and t=12t = \frac{1}{2}.
5(b) [4]
Find the positive value of tt at which the acceleration is zero. Hence find the total distance travelled between t=0t = 0 and this instant.
6
A car of mass 18001800 kg is towing a trailer of mass 300300 kg up a straight road inclined at an angle α\alpha to the horizontal, where sin⁡α=0.05\sin \alpha = 0.05. The car and trailer are connected by a tow-bar which is light and rigid and is parallel to the road. There is a resistance force of 800800 N acting on the car and a resistance force of FF N acting on the trailer. The driving force of the car's engine is 30003000 N.
6(a) [5]
It is given that F=100F = 100. Find the acceleration of the car and the tension in the tow-bar.
6(b) [5]
It is given instead that the total work done against FF in moving a distance of 5050 m up the road is 60006000 J. The speed of the car at the start of the 5050 m is 20m s−120 \text{m s}^{-1}. Use an energy method to find the speed of the car at the end of the 5050 m.

Published by Cambridge Assessment International Education. Reproduced for study use.