Probability & Statistics 2 — Variant 2

A Level Mathematics · 9709/62 · May/June 2023

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Questions

6 of 7 questions shown here, checked against the paper. The others are in the PDF above — they contain diagrams or maths we could not yet verify, and we would rather show you the original than a transcription we are not sure of.

1 [3]
In a survey of 200200 randomly chosen students from a certain college, 23%23\% of the students said that they owned a car. Calculate an approximate 93%93\% confidence interval for the proportion of students from the college who own a car.
2
2(a) [1]
The random variable WW has a Poisson distribution. State the relationship between E(W)\mathrm{E}(W) and Var(W)\mathrm{Var}(W).
2(b) [1]
The random variable XX has the distribution B(n,p)\mathrm{B}(n, p). Jyothi wishes to use a Poisson distribution as an approximate distribution for XX. Use the formulae for E(X)\mathrm{E}(X) and Var(X)\mathrm{Var}(X) to explain why it is necessary for pp to be close to 00 for this to be a reasonable approximation.
2(c) [3]
Given that YY has the distribution B(20000,0.00007)\mathrm{B}(20000, 0.00007), use a Poisson distribution to calculate an estimate of P(Y>2)\mathrm{P}(Y > 2).
3
The masses, in kilograms, of newborn babies in country AA are represented by the random variable XX, with mean μ\mu and variance σ2\sigma^{2}. The masses of a random sample of 500500 newborn babies in this country were found and the results are summarised below. n=500,Σx=1625,Σx2=5663.5n = 500, \Sigma x = 1625, \Sigma x^{2} = 5663.5
3(a) [3]
Calculate unbiased estimates of μ\mu and σ2\sigma^{2}. A researcher wishes to test whether the mean mass of newborn babies in a neighbouring country, BB, is different from that in country AA. He chooses a random sample of 6060 newborn babies in country BB and finds that their sample mean mass is 2.952.95 kg. Assume that your unbiased estimates in part (a) are the correct values for μ\mu and σ2\sigma^{2}. Assume also that the variance of the masses of newborn babies in country BB is the same as in country AA.
3(b) [5]
Carry out the test at the 1%1\% significance level.
4
The number, XX, of books received at a charity shop has a constant mean of 5.15.1 per day.
4(a) [1]
State, in context, one condition for XX to be modelled by a Poisson distribution. Assume now that XX can be modelled by a Poisson distribution.
4(b) [2]
Find the probability that exactly 1010 books are received in a 33-day period.
4(c) [4]
Use a suitable approximating distribution to find the probability that more than 180180 books are received in a 3030-day period. The number of DVDs received at the same shop is modelled by an independent Poisson distribution with mean 2.52.5 per day.
4(d) [3]
Find the probability that the total number of books and DVDs that are received at the shop in 11 day is more than 33.
5
5(a) [5]
Two random variables XX and YY have the independent distributions N(7,3)\mathrm{N}(7, 3) and N(6,2)\mathrm{N}(6, 2) respectively. A random value of each variable is taken. Find the probability that the two values differ by more than 22.
5(b)
Each candidate's overall score in a science test is calculated as follows. The mark for theory is denoted by TT, the mark for practical is denoted by PP, and the overall score is given by T+1.5PT + 1.5P. The variables TT and PP are assumed to be independent with distributions N(62,158)\mathrm{N}(62, 158) and N(42,108)\mathrm{N}(42, 108) respectively. You should assume that no continuity corrections are needed when using these distributions.
5(b)(i) [5]
A pass is awarded to candidates whose overall score is at least 9090. Find the proportion of candidates who pass.
5(b)(ii) [1]
Comment on the assumption that the variables TT and PP are independent.
6
When a child completes an online exercise called a Mathlit, they might be awarded a medal. The publishers claim that the probability that a randomly chosen child who completes a Mathlit will be awarded a medal is 13\frac{1}{3}. Asha wishes to test this claim. She decides that if she is awarded no medals while completing 1010 Mathlits, she will conclude that the true probability is less than 13\frac{1}{3}.
6(a) [2]
Use a binomial distribution to find the probability of a Type I error. The true probability of being awarded a medal is denoted by pp.
6(b) [3]
Given that the probability of a Type II error is 0.89260.8926, find the value of pp.

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