Probability & Statistics 2 — Variant 2

A Level Mathematics · 9709/62 · Oct/Nov 2020

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Questions

6 of 7 questions shown here, checked against the paper. The others are in the PDF above — they contain diagrams or maths we could not yet verify, and we would rather show you the original than a transcription we are not sure of.

1 [3]
On average, 11 in 5000050000 people have a certain gene. Use a suitable approximating distribution to find the probability that more than 22 people in a random sample of 150000150000 have the gene.
2
A six-sided die has faces marked 1,2,3,4,5,61, 2, 3, 4, 5, 6. When the die is thrown 300300 times it shows a six on 5656 throws.
2(a) [3]
Calculate an approximate 96%96\% confidence interval for the probability that the die shows a six on one throw.
2(b) [1]
Maroulla claims that the die is biased. Use your answer to part (a) to comment on this claim.
4 [8]
The areas, XX cm2\text{cm}^{2}, of petals of a certain kind of flower have mean μ\mu cm2\text{cm}^{2}. In the past it has been found that μ=8.9\mu = 8.9. Following a change in the climate, a botanist claims that the mean is no longer 8.98.9. The areas of a random sample of 200200 petals from this kind of flower are measured, and the results are summarized by Σx=1850\Sigma x = 1850, Σx2=17850\Sigma x^{2} = 17850. Test the botanist's claim at the 2.5%2.5\% significance level.
5
Customers arrive at a shop at a constant average rate of 2.32.3 per minute.
5(a) [1]
State another condition for the number of customers arriving per minute to have a Poisson distribution. It is now given that the number of customers arriving per minute has the distribution Po(2.3)\mathrm{Po}(2.3).
5(b) [2]
Find the probability that exactly 33 customers arrive during a 11-minute period.
5(c) [3]
Find the probability that more than 33 customers arrive during a 22-minute period.
5(d) [3]
Five 11-minute periods are chosen at random. Find the probability that no customers arrive during exactly 22 of these 55 periods.
6
A biscuit manufacturer claims that, on average, 11 in 33 packets of biscuits contain a prize offer. Gerry suspects that the proportion of packets containing the prize offer is less than 11 in 33. In order to test the manufacturer's claim, he buys 2020 randomly selected packets. He finds that exactly 22 of these packets contain the prize offer.
6(a) [5]
Carry out the test at the 10%10\% significance level.
6(b) [3]
Maria also suspects that the proportion of packets containing the prize offer is less than 11 in 33. She also carries out a significance test at the 10%10\% level using 2020 randomly selected packets. She will reject the manufacturer's claim if she finds that there are 33 or fewer packets containing the prize offer. Find the probability of a Type II error in Maria's test if the proportion of packets containing the prize offer is actually 11 in 77.
6(c) [1]
Explain what is meant by a Type II error in this context.
7
Before a certain type of book is published it is checked for errors, which are then corrected. For costing purposes each error is classified as either minor or major. The numbers of minor and major errors in a book are modelled by the independent distributions N(380,140)\mathrm{N}(380, 140) and N(210,80)\mathrm{N}(210, 80) respectively. You should assume that no continuity corrections are needed when using these models. A book of this type is chosen at random.
7(a) [5]
Find the probability that the number of minor errors is at least 200200 more than the number of major errors. The costs of correcting a minor error and a major error are 2020 cents and 5050 cents respectively.
7(b) [5]
Find the probability that the total cost of correcting the errors in the book is less than $190\$190.

Published by Cambridge Assessment International Education. Reproduced for study use.