Unit 12: Information Handling — Review Exercise
9th Class Mathematics · Unit 12: Information Handling
R12.1.Four options are given against each statement; encircle the correct option. Selected numerical parts: (vii) If the mean of 5, 7, 8, 9 and x is 7.5, what will be the value of x? (a) 10 (b) 8 (c) 8.5 (d) 5.8. (viii) Find the mode of the given data: 2, 5, 8, 9, 0, 1, 3, 7 and 10. (a) 5 (b) 7 (c) 0 (d) no mode. (x) Find the median of the given data: 110, 125, 122, 130, 124, 127 and 120. (a) 124 (b) 120 (c) 125 (d) 127.
Formula
(vii) Mean equation
5+7+8+9+x5 = 7.5
Working
29+x = 37.5
Result
x = 8.5 (option c)
(viii) Mode
no mode (option d), all values distinct
Given
(x) Sorted data
110,120,122,124,125,127,130
Result
Median
124 (option a, 4th term of 7)
R12.3.Following are the weights of 40 students recorded to the nearest (lbs): 138, 164, 150, 132, 144, 125, 149, 157, 146, 158, 140, 147, 136, 148, 152, 144, 168, 126, 138, 176, 163, 119, 154, 165, 146, 173, 142, 147, 135, 153, 140, 135, 161, 145, 135, 142, 150, 156, 145, 128. Make a frequency table taking size of class limits as 10. Also draw histogram and frequency polygon of the given data.
(a) Frequency table (class width 10)
119-128:4, 129-138:7, 139-148:13, 149-158:9, 159-168:5, 169-178:2
Result
Total
Sigma f = 40
(b), (c) Histogram and frequency polygon
plotted using midpoints 123.5,133.5,143.5,153.5,163.5,173.5
R12.4.From the table given below, draw a frequency polygon on histogram for the given frequency distribution. Weight (kg): 50–56, 57–59, 60–64, 65–72, 73–75, 76–80 with Frequency (f): 25, 32, 40, 30, 15, 8.
R12.5.Given below are marks obtained by 45 students in the monthly test of Biology: Marks 20–24, 25–29, 30–34, 35–39, 40–44, 45–49 with No. of students 05, 08, 12, 15, 03, 02. With reference to the above table find the following: (i) upper class boundary of the 5th class. (ii) lower class boundaries of all the classes. (iii) midpoint of all the classes. (iv) the class interval with the least frequency.
R12.6.Given below is frequency distribution. Draw frequency polygon and histogram for the distribution. Class limits: 5–9, 10–14, 15–19, 20–24, 25–29, 30–34 with Frequency: 1, 8, 18, 11, 2, 5.
Class boundaries and midpoints
4.5-9.5(7), 9.5-14.5(12), 14.5-19.5(17), 19.5-24.5(22), 24.5-29.5(27), 29.5-34.5(32)
Result
Histogram and frequency polygon
plotted using frequencies 1,8,18,11,2,5
R12.7.For the following data, find the weighted mean. Item: Chair (Quantity 20, Cost 500), Table (Quantity 20, Cost 400), Black board (Quantity 10, Cost 750), Tube light (Quantity 25, Cost 230), Cupboard (Quantity 09, Cost 950).
wx table
20(500)=10000, 20(400)=8000, 10(750)=7500, 25(230)=5750, 9(950)=8550
Working
Sigma w = 84, Sigma wx = 39800
Formula
Weighted mean
bar{X} = Sigma wXSigma w = 3980084
Result
= 473.81 rupees
R12.8.A principal of a school allocates funds of Rs. 50,000 to five different sectors: (i) chairs: Rs. 15000 (ii) tables: Rs. 12,000 (iii) black boards: Rs. 6,000 (iv) room renovation: Rs. 10,000 (v) gardening: Rs. 7,000. Find the average of funds allocation in each sector of the school.
Formula
Mean
bar{X} = Sigma Xn
Working
= 15000+12000+6000+10000+70005 = 500005
Result
= Rs. 10000
R12.9.The marks of a student Saad in six tests were 84, 91, 72, 68, 87, 78. Find the arithmetic mean of his marks.
Working
Mean
bar{X} = 84+91+72+68+87+786 = 4806
Result
= 80 marks
R12.10.Adjoining distribution showed maximum load (in kg) supported by certain ropes. Find the mean load using short method. Max-Load kg: 93–97, 98–102, 103–107, 108–112, 113–117, 118–122 with No. of ropes: 2, 5, 8, 12, 6, 2.
Short method, D=110
y=x-110: -15,-10,-5,0,5,10; fy: -30,-50,-40,0,30,20; Sigma fy = -70
Working
bar{Y} = -7035 = -2
Result
Mean
bar{X} = bar{Y}+110 = -2+110 = 108 kg
R12.11.Usman rolled a fair dice eight times. Each time their sum was recorded as 8, 5, 6, 6, 9, 4, 3, 11. Find the median and mode of the sum.
Given
Sorted data
3,4,5,6,6,8,9,11
Working
Median
Median = 12(4th+5th) = 12(6+6) = 122
Result
= 6
Mode
6 (most repeated term)
R12.12.Two partners Mr. Aslam and Mrs. Kalsoom run a company. In the following data the weekly wages (in Rs.) of employees who work in the company are given: Wages (Rs.): 600–700, 700–800, 800–900, 900–1000, 1000–1100 with Employees: 3, 5, 7, 21, 11. Find mean, median and mode.
Mean table
midpoints 650,750,850,950,1050; fx: 1950,3750,5950,19950,11550; Sigma f=47, Sigma fx=43150
Working
bar{X} = 4315047
Result
Mean
= 918.09
Median: cumulative frequency
3,8,15,36,47; n2=23.5, median class 900-1000, c=15, f=21, h=100
Working
900 + 10021(23.5-15)
Result
Median
= 940.48
Mode: modal class 900-1000
fm=21, f1=7, f2=11, h=100, l=900
Working
900 + 21-7(21-7)+(21-11) × 100
Result
Mode
= 958.33