Unit 4: Work, Energy and Power — Short Questions
11th Class Physics · Unit 4: Work, Energy and Power
Exercise Short Questions
When an elevator is descending, electrical power might still be required for:
1. Controlled descent: To ensure a smooth, controlled descent, and prevent free fall.
2. Braking: To slow down or stop the elevator safely.
A limit on the number of passengers is necessary for:
1. Safety: Overloading can cause mechanical stress, increasing the risk of accidents.
2. Controlled movement: Too many passengers can affect the elevator's ability to descend smoothly and safely.
These limits ensure safe operation and prevent potential hazards.
The expression for work done is dot product of force and displacement
W = F̄·d̄
W = Fd cosθ
The work done by Earth's gravity is negative, since force and displacement are in opposite direction (θ = 180°)
w = − Fd
The work done by person is positive, since, the force and displacement are in the same direction so, θ = 0°
W = FHcosθ = FH
Justification: (gravity pulls downward, opposite to displacement) So, it does negative work. The applied force does positive work to raise the body.
- Initial potential energy = 0
- Final potential energy = mgH
when an object falls towards Earth, then according to law of conservation of energy for non-resistance medium, it can be written as,
Mathematically:
loss in P.E = gain in K.E
This shows total mechanical energy remains conserved.
The law of conservation for resistive medium can be written as
Mathematically:
loss in P.E = given in K.E + work done against friction.
It is clear that a part of energy is converted into heat energy to perform work against friction so total mechanical energy does not remain conserved.
m = 1000 kg
h = 100 m
t = 20 s
P = ?
Work = w = m × g × h
= 1000 kg × 9.8 m/s² × 100 m
= 980,000 J
Power = Work / time
= 980,000 J / 20 s
= 49,000 W
= 49 kW
So, the power of crane is 49 kW.
Total mass = M₁ = initial mass of trolley + sandbags
= 1500 kg + 500 kg
= 2000 kg
Mf = 1500 kg
vi = 40 km/h = 40×1000/3600 = 11.11 m/s
vf = ?
Using principle of conservation of momentum:
Initial momentum = Final momentum
M₁vi = Mf vf
2000 × 11.11 = 1500 × vf
vf = (2000 × 11.11) / 1500
vf = 14.81 m / s
Here are the units
MKS System:
1. Absolute unit: Joule (J)
2. Gravitational unit: kilogram-meter (kg-m)
CGS System:
1. Absolute unit: erg
2. Gravitational unit: gram-centimeter (g-cm)
Note that:
1 Joule = 10⁷ ergs
Height = H, speed = V = 1.2√gh
Initial potential energy = mgH
Final kinetic energy
= 1/2 m v² = 1/2 m(1.2√(gH))² = 0.72mgH
Work done by gravity = mgh
Work done by air friction = change in mechanical energy
= final KE – initial PE
= 0.72mgH – mgH
= – 0.28mgH
So, work done by air friction is -0.28mgH.
The negative sign indicates energy loss due to friction.
Initial KE = 150 J = 1/2 m v²
(i) Double speed:
New KE = 1/2 m(2v)²
= 4 × 1/2 m v² (Putting value of initial K.E)
= 4 × 150 J
= 600 J
(ii) Three times mass, half speed:
New KE = 1/2 (3 m) (v / 2)²
= 1/2 × 3m × v²/4
= (3/4) × 1/2 m v² (Again putting value of K.E)
= (3/4) × 150 J
= 112.5 J
So, the new kinetic energies would be 600 J and 112.5 J, respectively.
∴K.E = p²/2m --------- (1)
If p' = 2p
K.E' = (2p)²/2m
K.E' = 4p²/2m
Using Eq. (1)
K.E' = 4K.E
Hence, when momentum is doubled then K.E becomes four times.
The International Space Station (ISS) has:
Gravitational Potential Energy (PE):
due to its height above Earth's surface. It is in orbit, but still within Earth's gravitational field. (P.E = −GMm/r)
Kinetic Energy: due to it is orbital velocity. K.E allows it to continuously fall around the Earth, maintaining orbit. (K.E = 1/2 m v²)
Both PE and KE are essential for the ISS's orbital motion.
SLO Based Additional Short Questions + Past papers Short Questions of Punjab Boards
Graphical representation of work
When a force F acts through a certain distance the event can be plotted by taking the distance along x-axis and the force along y-axis. The area under a force-displacement curve represent the work done by the force.
Characteristic of work
(i) Work is a scalar quantity.
(ii) If θ < 90°, work is done is said to the positive work.
(iii) If θ = 90°, no work is done.
(iv) If θ > 90°, the work done is said to be negative.
Work done by variable force
(i) A rocket moves away from the earth, work is done against the force of gravity, which varies as the square of distance from the earth's centre.
(ii) The force exerted by a spring increases with the amount of stretch.
Gravitational field
The space around the earth in which it's gravitational force acts on a body, is called the gravitational field.
Conservative field
The field in which the work done is independent of the path followed or work done in a closed path is zero, is called conservative field.
Non-conservative force
The frictional force is a non-conservative force, because if an object is moved over a rough surface between two points along different paths the work done against the frictional force is certainly different. Hence it is a non-conservative force.
Commercial unit of electric energy
Kilowatt hour is the commercial unit of electrical energy.
One Kilowatt-hour is the work done in one hour by an agency whose power is one kilowatt.
Therefore,
1kWh = 1000w × 3600s
= 3.6 × 10⁶ J = 3.6MJ
Absolute P.E.
The negative sign shows that the earth's gravitational force for mass m is attraction.
Work done
The work by a body is written as:
W = F̄.d̄ = Fd cos θ
In a circular path the centripetal force acting on the body is perpendicular to the direction of motion i.e. θ = 90°
w = F.d cos 90° = 0
w = 0
Work-energy principle
Work energy principle states that work done in accelerating the body is always equal to the change in its K.E. i.e.
Fd = 1/2 m vf² − 1/2 m vi²
If this body is raised against gravitational field with constant velocity. then according to work-energy principle.
Work done = Δ(P.E)
Or WA→B = (P.E)B − (P.E)A
Constructed Response Questions
A force is considered conservative if:
1. Work done is path-independent: The work done by the force on an object depends only on the initial and final positions, not on the path taken.
2. Work done in a closed loop is zero: When an object moves in a closed loop (returns to its initial position), the total work done by the conservative force is zero.
Examples: gravitational force, elastic force, electrostatic force.
∴ K.E = p²/2m ⟹ K.E ∝ 1/m When p = constant
This expression shows that light mass has greater K.E for same momentum.
Since motorcycle is moving with a constant speed, so there is no acceleration which clearly shows no net force acts and hence no work done i.e. w = Fd ⟹ (0) (d) = 0
Reason
The force is opposing the motion, causing the ball's speed to decrease from 14 m/s to 6 m/s. This means the force is acting opposite to the direction of motion, resulting in a decrease in kinetic energy, using work – energy principle,
w = 1/2 m vf² − 1/2 m vi²
As vf < vi, so work done will be negative.
The expression for K.E is expressed as:
Kinetic Energy (K.E) = ½mv²
A slow-moving truck can have more K.E than a fast-moving car if the truck's mass (m) is significantly larger than the mass of the car.
K.E depends on both mass and velocity, so a larger mass can compensate for lower velocity.
Actually, work done against friction is non-conservative in nature.
Reason: Frictional force opposes motion and converts mechanical energy into heat energy, which is dissipated and cannot be recovered. This energy loss makes friction a non-conservative force in nature. Secondly, work done by friction depends on path followed by the object.
Yes, wind contains kinetic energy (K.E).
Reason: Wind is moving air, and its motion gives it kinetic energy. The faster the wind blows; the more kinetic energy it possesses.
(K.E = 1/2 m v²)
Comprehensive Questions
See Q.7 of theory.
See Q.1 and 2 of theory.
See Q.3 and 4 of theory. (both proof will be shown).
See Q.8 of theory.
See Q.10 of theory.
See Q.9 of theory.